Lets say we have a Dragon born with Volume=v (v=xyz), Mass=m. It’s Density would be d=m/v. We also know that it kick ass with a Force=F, where F=m*a, being a the acceleration of it’s arms while punching.
If our DB double it’s size in every dimension, it means that it’s Volume is: V’=2x2y2z > V’=8(xyz) > V’=8V.
If we assume it’s density keeps constant, then it means it gains some mass.
D=m/v, but now D=m’/v’ so
m/v=m’/v’ , mv=m/(8v) , m8v/v=m’ , m’=8m
If we assume that it will punch with the same acceleration as always, F=m*a
F’=m’a, F’=8ma F’=8(m*a) F’=8F
So, changing from medium to large would imply changing 8 times the strength. If this keeps up for every step, then we are talking about one extra change to get to huge, and then one to get to gargantuan . So 8^3 times the force. And if we assume a linear relation between force and damage, 8^3 times the damage…
Doubling the size in each dimension should at least double the damage
My (very briefly) Gargantuan Wild Shaped Dire Wolf salivates at this thought.
Math time!!!
Lets say we have a Dragon born with Volume=v (v=xyz), Mass=m. It’s Density would be d=m/v. We also know that it kick ass with a Force=F, where F=m*a, being a the acceleration of it’s arms while punching.
If our DB double it’s size in every dimension, it means that it’s Volume is: V’=2x2y2z > V’=8(xyz) > V’=8V.
If we assume it’s density keeps constant, then it means it gains some mass.
D=m/v, but now D=m’/v’ so
m/v=m’/v’ , mv=m/(8v) , m8v/v=m’ , m’=8m
If we assume that it will punch with the same acceleration as always, F=m*a
F’=m’a, F’=8ma F’=8(m*a) F’=8F
So, changing from medium to large would imply changing 8 times the strength. If this keeps up for every step, then we are talking about one extra change to get to huge, and then one to get to gargantuan . So 8^3 times the force. And if we assume a linear relation between force and damage, 8^3 times the damage…
Yeah… A few extra d4s seems… Meh
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